Obtain the factors of z2–4z -12
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Answer:
Correct factors are 6 and -2 of equation z²-4z-12
Step-by-step explanation:
z²-4z-12 = 0
z²-6z+2z-12 = 0
z(z-6) + 2(z-6) = 0
(z-6) (z+2) = 0
1st case and 2nd case
z-6 = 0 z+2 = 0
z+2 z-6
z-6=0 and z+2 = 0
z=0+6. z=0-2
z= 6 z= -2
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