Question

) Obtain the quadratic equation if its roots are -7, -3​

Answer 1

Answer:

Step-by-step explanation:

given roots -7,-3

sum of roots =-7-3=-10

product of roots=(-7)(-3)=21

the quadratic equation is

$x^{2} -(sum of roots)x+(product of roots)=0$

$x^{2} -(-10)x+21=0\\x^{2} +10x+21=0$