obtain the quadratic equation if roots are 1)7,10
2)6,-13
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Step-by-step explanation:
1) let alpha=α=7 and beta=β=10
General form of the quadratic equation be x^2 + (α + β ) x + (αβ)
Now substituting α and β values...
=x^2 + (7 + 10 )x + (7 × 10 ) = x^2 + 17x + 70
∴ Required quadratic equation be x^2 + 17x + 70 = 0.
2) Let α = 6 and β = -13
Now substituting α and β values. ...
x^2 + (6 - 13)x + 6 (-13) = x ^2 -7x -78
∴ Required quadratic equation be x^2 - 7x -78 = 0.
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