Question

obtain the quadratic equation whose root are given -3 and -7​

Answer 1

Answer:

x²+10x+21=0

Step-by-step explanation:

p(x)= x²_sx+p=0

sum of zero=

$- 3 + ( - 7) \\ - 3 - 7$

=_10

product of zero=_3×_7=21

$x {}^{2} - sx + p \\ x {}^{2} + 10 + 21$

Answer 2

Answer:

The quadratic equation is x²+10x+21=0

Step-by-step explanation:

The formula is:

${x}^{2} - ( \alpha + \beta )x + \alpha \beta = 0$

where alpha and beta are two roots of the quadratic equation.

Here given two roots are -3 & -7.

The quadratic equation is x²+10x+21=0

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