Question

obtain the quadratic equation whose roots are 8 and -12​

Answer 1

Answer:

x^2 + 4x - 96

Explanation:

Let l and m be the roots f the quadratic equation.

l = 8

m = -12

Therefore l + m = -4 and lm = -96

If the quadratic equation is in the form of ax^2 + bx + c

Then - 4 = -b/a and -12 = c/a

Therefore taking a as 1

we get b = 4 and c = -96.

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Answer 2

Answer:

The roots of the quadratic equation are 3 and 8

Let α=8 and β=8

α+β=8+ (-12) =  -4

α×β = 8(-12) = -96

The required quadratic equation is

x2 −(α+β)x+α.β=0

∴ x2 -(-4)x+(-96)=0

x2+4x-96+0

That's all

Thank you!