Obtain the relationship between a and b, if 3 is one of the zero of (x) = axsquare− bx + 2
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Step-by-step explanation:
Answer
Correct option is
A
b−a+1
Let α,β be the other zeros of the given polynomial x
3
+ax
2
+bx
2
+c
Sum of the zeros =
coefficient of x
3
−coefficient of x
2
⇒−1+α+β=
1
−a
=−a
⇒α+β=−a+1 (i)
Again,
(−1)α+αβ+(−1)β=
coefficient of x
3
−coefficient of x
⇒−α+αβ−β=
1
b
=αβ=b+α+β
α+β=−a+1 , from (i))
=b−a+1
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