Question

Obtain the resonant frequency wr of a series LCR circuit with L = 2.0H, C = 32 μF and R = 10 W. What is the Q-value of this circuit?

Answer 1

Dear Vani,

◆ Answer -

ω = 125 Hz

Q-value = 25

● Explanation -

# Given -

L = 2 H

C = 32 μF = 32×10^-6 F

R = 10 W

# Solution -

Resonant frequency of the circuit is given as -

ω = 1/√(LC)

ω = 1/√(2×32×10^-6)

ω = 1/(8×10^-3)

ω = 125 Hz

Q-value of the given circuit is calculated as -

Q-value = (1/R) √(L/C)

Q-value = 1/10 √(2/32×10^-6)

Q-value = 25

Thanks dear...

Answer 2

Answer:

The resonant frequency is given by

ωr=1/LC=1/2×32×10^−6

⇒125rad/s

The Q value of the circuit is given by:

Q=1/R* under root 1/CL=1/10 under root 2÷32×10^−6

⇒Q=25