Question

Obtain the roots of quadratic equation x^2+19x+48=0 by formula​

Answer 1

Answer:

-3 and -6

Step-by-step explanation:

By quadratic formula:

x = -b +- √(b^2-4ac) ÷ 2a

Therefore by putting values of a, b and c,

x = -19 +- √(361-192) ÷ 2

x = -19 +- √169 ÷ 2

x = -19 +- 13 ÷ 2

x = -19 + 13 ÷ 2 and -19 - 13 ÷ 2

x = -6 ÷ 2 and -32 ÷ 2

x = -3 and -16

Therefore, roots of the quadratic equation are: -3 and -6

Hope I was able to help you. If yes,. please do upvote and mark my answer as the brainliest!!