Question

obtain the sum 34+32+.....+10​

Answer 1

Answer:

Your series answer is 34 + 32 + ...........+ 10 = 286

Answer 2

Step-by-step explanation:

Considering 34+32+......+10 as an AP;

a=34

d=32-34=-2

so,

an=a+(n-1)d

10=34+(n-1)-2

10=34-(-2n+2)

10=34+2n-2

10=32+2n

10-32=2n

-22=2n

-22/2=n

-11=n

now sum=sn=n/2(2a+(n-1)d)

=-11/2(2*34+-12*-2)

=-11/2(68+24)

=-11/2(92)

=-1012/2

=-506