obtain the sum 34+32+.....+10
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Answer:
Your series answer is 34 + 32 + ...........+ 10 = 286
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Step-by-step explanation:
Considering 34+32+......+10 as an AP;
a=34
d=32-34=-2
so,
an=a+(n-1)d
10=34+(n-1)-2
10=34-(-2n+2)
10=34+2n-2
10=32+2n
10-32=2n
-22=2n
-22/2=n
-11=n
now sum=sn=n/2(2a+(n-1)d)
=-11/2(2*34+-12*-2)
=-11/2(68+24)
=-11/2(92)
=-1012/2
=-506
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