obtain the sum of first 48th term of an A.P whose 21st term is 72 &28 term is 156
obtain the sum of first 48th term of an A.P whose 21st term is 72 &28 term is 156
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Answer:
a+27d=156
a+20d=72
change the sign to minus then you will obtain
7d=84
d=84/7
d=12
put the value of d in any one equation
a+20d=72
a+20(12)=72
a+240=72
a=168
now we can find the sum of 48th term
sum =n/2(2a+(n-1)*d
=48/2(2*168+47*12)
24*900
=21600 is the sum of 48 terms
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