obtain the sum of first fifteenth term of an A.P. whose first term is 10 and common difference is -7
Answers
Answered by
2
Answer:
sn = - 585
Step-by-step explanation:
n= 15
a = 10
d = -7
an = a + (n-1)d
an = 10 + (15 -1 )-7
an = 10 + (-98)
an = - 88
sn = n/2(a + an )
sn = 15/2 ( 10 - 88)
sn = 15/ 2( - 78)
sn = - 585
Answered by
0
Sum of first 15 terms=15/2(2*10+(15-1)(-7)
=15/2(20-14*7)=15/2(20-98)=15/2(-78)
=15(-39)
=-585
=15/2(20-14*7)=15/2(20-98)=15/2(-78)
=15(-39)
=-585
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