Math, asked by shilap643, 8 months ago

Obtain the sum of the integers in the first 100 positive integer which are neither divisible by 5 nor 2.

Answers

Answered by ghtyu66
0

Step-by-step explanation:

if the sum of first n number is 100 so n=100 for 2

we use n/2[2a+(n-1)d]

a=2

d=2

we get 10100

for 5

a=5

d=5

we get 252500

for 10

a=10

d=10

we get 50500

10100+252500-50500=212100

Similar questions