Question

Obtain the zeros of root3x²-8x+4root3 and find the relationships between the zeros and coefficients​

Answer 1

Ans:- √3x²-8x+4√3

= √3x²-6x - 2x + 4√3

= √3x(x-2√3) - 2(x - 2√3)

= (x - 2√3)(√3x - 2)

=> x - 2√3 = 0

=> x = 2√3

=> √3x - 2 = 0

=> √3x = 2

=> x = 2/√3

hence 2√3 and 2/√3 are the zeroes of the polynomials.

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