Question

Obtain zeroes of the polynomial

$x {}^{2} \: + \: 7x \: \: + \: 12$

Answer 1

HOLA

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$x {}^{2} \: - \: 7x \: + \: \: 12 \\ \ \\ x {}^{2} - \: 4x \: + \: 3x \: + \: 12 \\ \\ x \: ( \: x \: + \: 4 \: ) \: + \: 3 \: ( \: x \: + \: 4 \: ) \\ \\ ( \: x \: + \: 4 \: ) \: + \: ( \: x \: + \: 3 \: ) \\ \\ \: x \: = \: - 4 \: \: x \: = \: - 3$

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The two zeroes are - 4 , - 3

HOPE U UNDERSTAND ☺☺☺

Answer 2

x² + 4x + 3x + 12 = 0


=> x( x + 4) + 3( x + 4 ) = 0

=> ( x + 4 ) (x + 3 ) = 0

=> x= -4 or -3





$\fcolorbox{red}{aqua}{zeroes \: \: are \: \: - 3 \: and \: \: - 4}$