Question

Obtain zeros of polynomial √3x^2-8x+4√3 and verify the relation between it's zeros and coefficient​

Answer 1

Step-by-step explanation:

√3x²-8x+4√3

√3x²-6x-2x+4√3

√3x(x-2√3)-2(x-2√3)

(x-2√3)(√3x-2)

Roots are:- x=2√3 and x=2/√3

By using property of coefficients are:

alpha= 2√3 and beta= 2/√3

Sum of its zeroes= -coefficient of x/ coefficient of x² =-b/a

= 2√3+2/√3= 8/√3

= 8/√3 =8/√3

Product of its zeroes= constant term / coefficient of x =c/a

=2√3*2/√3 = 4

= 4=4

=> Verified!!

Hope this helps you!!!!