OC is the bisector of angle AOB,P is any point on OC.From P,PM and PN are drawn perpendicular on OA and OB respectively. prove that MP= NP
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OC is the bisector of angle AOB.
OA&OB are perpendicular [45degrees].
PM+MQ=PQ
PN+NR=PR
Take 2 tangents & add
PM=PQ+QN
PM=PN
Hence Proves
OA&OB are perpendicular [45degrees].
PM+MQ=PQ
PN+NR=PR
Take 2 tangents & add
PM=PQ+QN
PM=PN
Hence Proves
sweetteacher:
can you please elaborate it
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Given
OC bisects ∠AOB
PM and PN ⊥ OA andOB
To prove:MP=NP
proof:
In ΔMOP and ΔNOP
∠OMP=∠ONP=90°
∠MOP=∠NOP (∵OA bisects ∠AOB)
OP=OP (common)
∴ΔMOP≈ΔNOP (AAS congruence rule)
so,
MP=NP (By CPCT)
Hence proved!
Hope it helps u!!!!!!!!!!
nd plzzzzzzzmark it as the brainliest answer!!!!!!!!!!!!
OC bisects ∠AOB
PM and PN ⊥ OA andOB
To prove:MP=NP
proof:
In ΔMOP and ΔNOP
∠OMP=∠ONP=90°
∠MOP=∠NOP (∵OA bisects ∠AOB)
OP=OP (common)
∴ΔMOP≈ΔNOP (AAS congruence rule)
so,
MP=NP (By CPCT)
Hence proved!
Hope it helps u!!!!!!!!!!
nd plzzzzzzzmark it as the brainliest answer!!!!!!!!!!!!
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