Ocm angle? 2 POR if I (PQ) = (3x - 1). 1 (QR) = 15x and I (PR) = (15x + 1). then for ch value of x will APQR be a right angled triangle? (2
) 6 (3) 4 (4)
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In ΔPQR, O is a point in it such that
OP=6cm, OR=8cm and ∠POR=90°
PQ=24cm, QR=26cm
Now,
In ΔPOR, ∠O=90°
o
PR²=PO² +OR²
=(6)
2
+(8)
2
=36+64
=100
PR=10
Greatest side QR is 26cm
QR
2
=(26)
2
=676
and PQ² +PR² =(24)² +(10)² =576+100 =676
Which implies, 676=676
QR² =PQ² +PR²
ΔPQR is a right angled triangle and right angle at P.
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