Question

Octahedral crystalline variety of sulphur contain ''X'' S-S bonds in which covalency of sulphur =y. It contains ''Z'' lonepair of electrons, then (z - x - y)=​

Answer 1

Explanation:

Octahedral crystalline variety of sulphur contain ''X'' S-S bonds in which covalency of sulphur =y.

They are S8 crown sulphur molecule.

x = no of S bonds

x = 8

y = covalency no of bonds and atoms form

y = 2

z = lone pairs

z = 16

therefore

z - x - y = 16 - 8 - 2

= 6