Math, asked by legend28, 1 year ago

∆ODC~∆OBA,BOC=125° and CDO=70°,find angle DOC, angle DCO and angle OAB

Answers

Answered by ishikabindal
2
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Answered by arlinmonica14
8

Answer:

Step-by-step explanation:

Angle DOC+angle BOC=180°

Angle DOC=180°-125°

Angle DOC=55°

Angle DOC+angle DCO+angle ODC=180°

Angle DCO=180°-125°

Angle DCO=55°

Angle OAB=angle OCB

Angle OAB=55°

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