Odd man out from coke, diamond, graphite,fullerene
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odd man out is graphite
vinaydakshin30:
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Final answer: The odd one out is coke.
Given that: We are given coke, diamond, graphite, and fullerene.
To find: We have to find the odd man out.
Explanation:
The correct answer is coke. The odd one out is coke.
- Coke is the only amorphous allotrope of carbon among all the other three.
- May have short-range order, i.e. some order lasting only short distances, but no complete regularity in the three-dimensional arrangement of structural units.
- The purest form of carbon.
- Melt over a wide temperature.
- Give uneven surface when cut.
- Easily distorted by even mild bending and compressing force.
Diamond, graphite, and fullerene are not the correct answer.
- Diamond, graphite, and fullerene are coming under crystalline allotropes of carbon.
- Have a repeating well-ordered geometrical pattern throughout the entire three-dimensional arrangement of their structural units, and thus have long-range orders.
- All have sharp melting points.
- Hence, diamond, graphite, and fullerene are not the correct answer.
To know more about the concept please go through the links
https://brainly.in/question/8141050
https://brainly.in/question/12919320
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