Chemistry, asked by Hercules2276, 1 year ago

Odd man out from coke, diamond, graphite,fullerene

Answers

Answered by sarthak9949
27

odd man out is graphite


vinaydakshin30: How??
Answered by abhijith91622
1

Final answer: The odd one out is coke.

Given that: We are given coke, diamond, graphite, and fullerene.

To find: We have to find the odd man out.

Explanation:

The correct answer is coke. The odd one out is coke.

  • Coke is the only amorphous allotrope of carbon among all the other three.
  • May have short-range order, i.e. some order lasting only short distances, but no complete regularity in the three-dimensional arrangement of structural units.  
  • The purest form of carbon.
  • Melt over a wide temperature.
  • Give uneven surface when cut.
  • Easily distorted by even mild bending and compressing force.

Diamond, graphite, and fullerene are not the correct answer.

  • Diamond, graphite, and fullerene are coming under crystalline allotropes of carbon.
  • Have a repeating well-ordered geometrical pattern throughout the entire three-dimensional arrangement of their structural units, and thus have long-range orders.
  • All have sharp melting points.
  • Hence, diamond, graphite, and fullerene are not the correct answer.

 

To know more about the concept please go through the links

https://brainly.in/question/8141050

https://brainly.in/question/12919320

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