Question

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Answer 1

Answer:

the probability is 2/3

Step-by-step explanation:

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Answer 2

The desired event E is to get at least two heads. E = {HHH, HHT, HTH, THH}. So, n(E) =4. Therefore the probability of getting at least two heads when three coins are simultaneously tossed = n(E)/n(S) = 4/8 =1/2.

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