Question

OEQ, and 5 tano=4 then 5 sino - 3 cos theta/ sino+2cos theta​

Answer 1

Answer:

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Step-by-step explanation:

Correct option is

B

6

1

Divide the numerator and denomenator by cosθ

cosθ

5sinθ+2cosθ

cosθ

5sinθ−3cosθ

⇒

cosθ

5sinθ

+

cosθ

2cosθ

3cosθ

5sinθ

−

cosθ

3cosθ

⇒

5tanθ+2

5tanθ−3

Substituting the value of 5tanθ, we get

⇒

4+2

4−3

=

6

1

Answer 2

Step-by-step explanation:

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