OEQ, and 5 tano=4 then 5 sino - 3 cos theta/ sino+2cos theta
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Answered by
0
Answer:
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Step-by-step explanation:
Correct option is
B
6
1
Divide the numerator and denomenator by cosθ
cosθ
5sinθ+2cosθ
cosθ
5sinθ−3cosθ
⇒
cosθ
5sinθ
+
cosθ
2cosθ
3cosθ
5sinθ
−
cosθ
3cosθ
⇒
5tanθ+2
5tanθ−3
Substituting the value of 5tanθ, we get
⇒
4+2
4−3
=
6
1
Answered by
1
Step-by-step explanation:
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