Question

of 0.2 mol of compound is required then how many grams should be taken mgcl​

Answer 1

Answer:

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Answer 2

Answer:

Explanation:

For starters, we know that a  

1-M

solution contains  

1

mole of solute for every  

1.0 L

of solution.

This implies that a  

4.5-M

magnesium chloride solution will contain  

4.5

moles of magnesium chloride, the solute, for every  

1.0 L

of solution.

So all you have to do now is figure out how many moles of magnesium chloride would be equivalent in  

2.0 L

of solution to  

4.5

moles in  

'

1.0

L

of solution.

?

.

moles MgCl

2

2.0 L solution

=

= 4.5 M solution



4.5 moles MgCl

2

1.0 L solution

Use cross multiplication to get

?

=

2.0

L solution

1.0

L solution

⋅

4.5 moles MgCl

2

This will be equal to

?

=

9.0 moles MgCl

2

So, you know that you can get a  

4.5-M

magnesium chloride solution by dissolving  

9.0

moles of magnesium chloride in enough water to have a total volume of  

2.0 L

of solution.

To convert this to grams, use the compound's molar mass

9.0

moles MgCl

2

⋅

95.211 g

1

mole MgCl

2

=

860 g

−−−−−  

The answer is rounded to two sig figs, the number of sig figs you have for your values.

Explanation:

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