Question

of 1 and -2 are the two zeros of the polyn
( x^3 - 4x² - 4x+10). find and its third zero​

Answer 1

Answer:

5

Step-by-step explanation:

The question is incorrect. The equation should be $x^3-4x^2-7x+10$

You can consider either sum of the roots, sum of product of roots taken two at a time, or product of roots.

For a cubic polynomial $ax^3+bx^2+cx+d$ with roots α, β, γ

α + β + γ = $\frac{-b}{a}$

αβ + βγ + γα = $\frac{c}{a}$

αβγ = $\frac{-d}{a}$

Let the unknown root be 'p'

p + 1 - 2 = 4

=> p = 5

(OR)

[p][1] + [1][-2] + [-2][p] = -7

=> p - 2 - 2p = -7

=> -p = -5

=> p = 5

(OR)

[p][1][-2] = -10

=> -2p = -10

=> p = 5