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of 10th team of AP is 52 and 17th term
of A.P is 20 more then 13th term
find AP
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Step-by-step explanation:
Given the 10'th term of an AP is 52 and its 17'th term is 20 more than its 13'th term
We have to find out,
The AP and its 30'th term
10'th term is 52 i.e. t₁₀ = a + 9d
a + 9d = 52 (given) -----[1]
its 17th term is 20 more than its 13th term
t₁₇ = 20 + t₁₃
⇒ a + 16d = 20 + a + 12d
⇒ 4d - 20 = 0
⇒ 4d = 20
⇒ d = 5
Substitute 'd' in [1]
We get,
⇒ a + 9d = 52
⇒ a + 45 = 52
⇒ a = 7
30'th term = a + 29d
7 + (29 * 5) = 152
Required answer:
AP = 7 , 12 , 17 , 22 , 27
30'th term = 152
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