Question

of 12 different books a self will hold five, how many arrangements may be made on the self
(permutation)​

Answer 1

Answer:

95040 ways

Step-by-step explanation:

Since there are 5 places and all 12 books are different

then 5 books can be selected in 12C5 ways and then arranged in 5 places in 5! ways. Or simply we can apply 12P5 that is

12!/7!= 12*11*10*9*8=95040 ways

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