Question

of 12 different books a self will hold five, how many arrangements may be made on the self
(can anyone explain it without formula)​

Answer 1

Answer:

95040

Step-by-step explanation:

we know that we have 12 books that are different and the 5 places are different too

For placing a book in first place we have 12 books. After placing one out of twelve books we are left with 11 books .

For placing another book in second place we have 11 books. After placing one out of 11 books we are left with 10 books .

For placing a book in third place we have 10 books . After placing one out of 10 books we are left with 9 books .

For placing a book in fourth place we have 9 books . After placing one out of 9 books we are left with 8 books .

For placing a book in last place that is fifth place we have 8 books.

Since these events are dependent on each other as we want TO ARRANGE THEM , by principle of multiplication we multiply all the available options

that is 12.11.10.9.8= 95040 ways.

Please mark it as brainliest

Thanks.