of ² ty² - 16 and xy =5, find the value of (1/3x_1/3y)
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Answer:
Correct option is A)
3x+4y=16
Squaring both sides
=>(3x+4y)
2
=256
=>9x
2
+16y
2
+2(3x)(4y)=256
=>9x
2
+16y
2
+24xy=256
=>9x
2
+16y
2
=256−24×4
=>9x
2
+16y
2
=256−96
=>9x
2
+16y
2
=160
Sana mka tulong
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