Question

of 24 kgs of salt water 8% is salt.of another mixture 4% is salt. How many kgs of the second mixture should be added to the 1st mixture in order to get a mixture that is 5%?​

Answer 1

Answer:

72 kg.

Step-by-step explanation:

Given that, 24 kg of saltwater has 8% salt.

So, the saltwater has (24*0.08)=1.92 kg of salt and (24-1.96)=22.08 kg of water. ...... (1)

Let us assume that x kg of another mixture where 4% is salt, is to be added to the above mixture to get a mixture where 5% is salt.

So, in x kg of the other mixture 0.04x kg will be salt and (x-0.04x)= 0.96x kg will be water. ...... (2)

Hence, when (1) and (2) are added then (24+x) kg of the mixture will have (1.92+0.04x) kg of salt.

So, the % of salt in the final mixture will be 5%.

Hence, $\frac{0.04x+1.92}{24+x} =\frac{5}{100}$

⇒ 0.04x+1.92= 1.2+0.05x

⇒0.01x=0.72

⇒ x=72 kg.

(Answer)