Math, asked by karabibarman929, 13 days ago

Of(3)3000- (3)2999-(3)2998+(3)2997=a.(3)2998,then find the value of a

Answers

Answered by vinpnm

2

Answer:

ANSWER

Step-by-step explanation:

Step-by-step explanation:3^2999(3^2+1)/3^2998(3^2-1)

Step-by-step explanation:3^2999(3^2+1)/3^2998(3^2-1)= 3×10/8 = 15/4

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