Question

of 3 and 4are zeroes of polynomial x²+(a+2)x+b then find a and b​

Answer 1

$a = 7. \: b = 14.$

Step-by-step explanation:

$let \: the \: two \: zeroes \: be \: \alpha \: and \: \beta .$

$\alpha = 3. \: \: \beta = 4.$

$sum \: of \: the \: zeroes \: ( \alpha + \beta ) = 3 + 4 = 7.$

$product \: of \: the \: zeroes = ( \alpha . \beta ) = 3 \times 4 = 12.$

$\: a = 7. \: b = 14.$

${x}^{2} + (7 + 2)x + 14.$

${x}^{2} + 9x + 14.$