Question

Of 3 angles of a triangle, one angle is double the smallest and another is triple the smaller angle. Find all the angles of the triangle. P

Answer 1

• Let the smallest angle be

= x

• 2nd angle

= double of smallest angle

= 2x

• 3rd angle

= Triple the smallest angle

= 3x

Sum of all angles in triangle = 180

x + 2x + 3x = 180

6x = 180

x = 30

Find measure of each angle :-

1st angle = x = 30°

2nd angle = 2x = 60°

3rd angle = 3x = 90°

Answer 2

✯✯ QUESTION ✯✯

Of 3 angles of a triangle, one angle is double the smallest and another is triple the smaller angle. Find all the angles of the triangle..

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✰✰ ANSWER ✰✰

$⇢Let\:First\:Angle=y$ (Smallest Angle)

$⇢Let\:Second\:Angle=2y$ (Double of smallest angle)

$⇢Let\:Third\:Angle=3y$ (Triple of Smallest angle)

Now : -

Sum of Angles of A Triangle=180°

$⇢y+2y+3y=180$

$⇢y+5y=180$

$⇢6y=180$

$⇢y=\cancel\dfrac{180}{6}$

➜$\small{\boxed{\bold{\bold{\red{\sf{y=30}}}}}}$

_______________________

☛$First\:Angle=\textbf{30°}$

☛$Second\:Angle=2y$

$⇢2(30)$

$⇢\textbf{60°}$

☛$Third\:Angle=3y$

$⇢3(30)$

$⇢\textbf{90°}$