of 3 boxes the first and second together contain rupees 400, II and III rupees 475 and the first and the third rupees 625 . find the amount in each Box .
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Answered by
1
1st- 275
2nd- 125
3rd- 350
Answered by
4
Let box 1 = x
box 2 = y
box 3 = z
Then we have:
x + y = 400......(1)
y + z = 475.......(2)
x + z = 625......(3)
From equation (2)
z = 475 - y........(4)
Substitute equation (4) in eq (3)
x + z = 625
x + 475 - y = 625
x - y = 625 - 475
x - y = 150...(5)
Elimination method on eq (1) and (5)
x + y = 400
x - y = 150
_________
2x = 550
x = 275
Substitute x = 275 in eq (1)
x + y = 625
y = 625 - 275
y = 350
Substitute y = 350 in eq (2)
y + z = 475
z = 475 - 350
z = 125
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