Question

Of 4 sin 0 = 3 cos find the value of - (i) Sin 0 i) Cot²0 - Cosec²0​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

4sin0=3sin0

sin0/cos0=3/4

tan0=3/4. {tan0= perpendicular/base}

so if a right triangle has perpendicular 3cm and base 4cm then by pythgoras law,

(hypteneous)²= (base)² + perpendicular²

hypotenuse² = 4²+3²

hypotenuse²= 16+9 =25

hypotenuse=5² = 5

so,

1) sin0 = perpendicular/hypotenuse

= 3/5

2) cot²0 - cosec²0 = cos²0/sin²0 - 1/sin²0

=5²/3²/3²/5² - 1/3²/5²

25/9/9/25 - 25/9

625/81 -25/9

625/81 -225/81

400/81