Question

OF A = 2,B=3 FIND THE VALUES OF (A^b + B^a)^-1​

Answer 1

Answer:

$\huge\underline{\overline {\mid {\bold{\red{ληsωεя}}\mid}}}$

$a = 2 \: \: \: \: b = 3$

${a}^{b} + {b}^{a} - 1$

$= > {2}^{3} + {3}^{2} - 1$

$= > 8 + 9 - 1$

$= > 17 - 1$

$= > 16$

Answer 2

Answer:

16 is the answer

Step-by-step explanation:

A=2,B=3

(A^b+B^a)-1=(2^3+3^2)-1

=(8+9)-1

=17-1

=16