of A.P. t2 is 4 and d is -4 what is the value of a
Answers
Answered by
3
Answer:
tn = a + (n-1)d
here n is 2
so
t2 =4 = a+(1)(-4)
4=a-4
a=8
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Answered by
1
Answer:
T2= a+(n-1)d
4 = a+(2-1)-4
4= a+(-4)
4= a-4
a= 4+4
a=8
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