of a train accelerating uniformly at 5m/s2 attains a velocity of 90km/h. After the start,find its displacement and time for which it accelerates?
Answers
Answered by
1
when the train start displacement=0
initial velocity (u)=0
final velocity(v)=90km/h=25m/s
acceleration=5m/se
time(t)=?
v=u+at
25=0+5×t
25=5×t
25=5t
25/5=t
5=t
time=5sec
initial velocity (u)=0
final velocity(v)=90km/h=25m/s
acceleration=5m/se
time(t)=?
v=u+at
25=0+5×t
25=5×t
25=5t
25/5=t
5=t
time=5sec
Similar questions