Question

Of alpha and beta are zeroes of polynomial x^2-x-2. Find a polynomial whose zeroes are (2alpha +1)and (2beta+1)

Answer 1

x^2-x+3 is the correct answer of this question

Answer 2

Answer:

first split the middle term of x^2-x-2

x^2+x-2x-2

x(x+1)-2(x+1)

(x+1)(x-2)

ZEROES: -1 and +2

Now, we have to form a quadratic equation for the following:-

x^2-(2alpha+1+ 2beta+1)x+(2apha+1*2beta+1)

Putting the values of the following:-

x^2-(2*(-1)+1 + 2*2+1)x+(2*(-1)+1*2*2+1)

x^2-4x+-5

Step-by-step explanation: