Of an AP, t6=15, d=8, Find t1 and t10
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Answer:
t1 is -25 and t10 is
Step-by-step explanation:
t6= a+5d
15= a+5(8)
15= a+40
a= -25
therefore t1 is a which is -25
for t10
t10= a+9(d)
t10= -25+9(8)
t10 = 47
the ap is -25, -17, -9, -1, 7, 15........
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