Question

of
@ T10 of an AP= 31 and T20=71
then
T30=?
117/ (6)222 (CJ 112 CD 14
o which term of the AP 3,81 13,8.
78.
Las 6 16
TO 17 (d) 18
o Iman A Pa = 1 , tri 30 andsn=399
then mis
la 19
J 38 (d) 28​

Answer 1

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Step-by-step explanation:

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Answer 2

Answer:

10th term = 31

a + 9d = 31

a = 31 - 9d -----1equation

20th term = 71

a + 19d = 71

a = 71 - 19d

From 1equation,

31 - 9d = 71 - 19d

19d - 9d = 71 - 31

10d = 40

d = \frac{40}{10}d=1040

d = 4

Putting the value of d in 1equation,

a = 31 - 9d

a = 31 - 9(4)

a = 31 - 36

a = -5

Now,

30th term = a + 29(d)

30th term = -5 + 29(4)

30th term = -5 + 116

30th term = 111

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