Question

of Calculate compound interest when p= Rs 6000,
R=9% per annum, time na 2 years​

Answer 1

Answer:

$Here, P=6,000 , R=9%=1009=0.09 and n=18months=1218=23 years.</p><p></p><p>Amount after 2 years =P(1+2r)2n </p><p></p><p>                      =6,000(1+20.09)223 </p><p></p><p>                      =6000(1+0.45)3 </p><p></p><p>                      =6,000×1.453=18291.75 </p><p></p><p>∴Amount=18291.75</p><p></p><p>∴C.I=A−P=18291.75−6000=12,291.75</p><p></p><p>C.I=12,291.75</p><p></p><p>$

Answer 2

Answer:

Amount =  

Given :

Principal = Rs. 6000

Time Period = 2 years

Rate of interest = 9%

Substituting in the formula we get,

=> Amount = 6000 ( 1 + 9 / 100 )²

=> Amount = 6000 ( 1 + 0.09 )²

=> Amount = 6000 ( 1.09 )²

=> Amount = 6000 ( 1.1881 )

=> Amount = 7128.60

Hence the amount is Rs. 7128.60

Compound Interest = Amount - Principal

=> CI = 7128.6 - 6000.0

=> CI = 1128.6

Hence it is the required answer.

Step-by-step explanation:

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