Question

of cos theta + sec theta = 2 , then sec^2 theta - sin^2 theta =​

Answer 1

Answer:

Correct option is

B

4

17

cosθ+secθ=

2

5

⇒(cosθ+secθ)

2

=(

2

5

)

2

, square both sides

⇒cos

2

θ+2cosθ⋅secθ+sec

2

θ=

4

25

⇒cos

2

θ+sec

2

θ=

4

25

−2(∵cosθ⋅secθ=1)

⇒cos

2

θ+sec

2

θ=

4

17

.