Question

of cosA= 12/13,then find sinA and tana ​

Answer 1

Step-by-step explanation:

(hypotenuse)2 = (perpendicular)2 + (base)2

⇒ (perpendicular)2 = (hypotenuse)2 – (base)2

⇒ (perpendicular)2 = (13)2 – (12)2

⇒ (perpendicular)2 = 169 – 144 = 25

⇒ perpendicular = √25 = 5

Using perpendicular = 5, base = 12 and hypotenuse = 13, we can find out sin A and tan A.

sin A 5/13

tan A 5/12

Answer 2

Cos A = 12/13

Cos = Adjacent side/Hypotenuse

Adjacent = 12, Hypotenuse = 13

AC = 13

AB = 12

BC² = AC² = AB² (Pythagoras theorem)

BC² = 13² - 12²

        = 169 - 14

BC²   = 25

BC = √25

     = 5

Sin A = Opposite side/ Hypotenuse

          = 5/13

Tan A = Opposite side/ Adjacent

            = 5/12

(Attachment of the figure is attached)