Question

of
Find the perimeter of a
triangle whose
sides are 2x+5y, 8x+6y,x-6y​

Answer 1

Question

Find the perimeter of triangle whose sides are 2x+5y,8x+6y,x-6y

Answer

Given :-

1st side : 2x+5y

2nd side : 8x+6y

3rd side : x-6y

To find :-

• Perimeter : ??

Formula used :

Perimeter of triangle : Sum of all its side

According to the question,

Perimeter of triangle = Sum of all its side

= 2x+5y + 8x+6y + x-6y

= 2x + 8x + x + 5y + 6y - 6y

= 11x + 11y - 6y

= $\fbox{11x - 5y}$

.°. Perimeter of triangle is $\sf{11x + 5y }$

Answer 2

Answer:

Given Information:-

Sides of the triangle:-

• 1st side = (2x + 5y) units
• 2nd side = (8x + 6y) units
• 3rd side = (x - 6y) units

To Find:-

Perimeter of the given triangle with the sides given.

_____________________...

We know

Perimeter of a triangle = Sum of all it's sides.

So, let's proceed! Since the sides are algebraic expressions, we have to add the like terms! That is, to simplify 'em.

.............

➡ (2x + 5y) + (8x + 6y) + (x - 6y)

(Formed an expression as per the Perimeter formula)

➡ 2x + 5y + 8x + 6y + x - 6y

(Brackets are removed)

➡ (2x + 8x + 1x) + [5y + 6y + (- 6y)]

(Separated the like terms in two brackets. 1st bracket only consists of x common terms and second, y common terms)

➡ 11x + (5y + 6y - 6y)

[(+) + (-) = (-)]

➡ 11x + 5y

(+ 6y and - 6y are cancelled \ ANSWER)

..............................................

Required Answer:-

Therefore, perimeter of the ∆ is (11x + 5y).