Question

of I m- canvas is Rs 70.
5. What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m
and base radius 6 m? Assume that the extra length of material that will be required for
stitching margins and wastage in cutting is approximately 20 cm (Use n = 3.14).​

Answer 1

Answer:

Tarpaulin is the curved surface area of tent

The height of tent h=8m

And radius of tent r=6m

Then slant height of tent l=

r

2

+h

2

=

(6)

2

+(8)

2

=

36+64

=

100

=10

Curved surface area of tent =3.14×6×10=188.4m

2

Area of tarpaulin material = area of tent

length×breadth=Curved surface area of tent

lenght×3=188.4

⇒Length=

3

188.4

=62.8m

The wastes in tarpaulin =20cm=0.2m

Then length of tarpaulin =62.8+0.2=63m

Answer 2

Answer:

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