Question

of ice at -10°C to water at 100°C is 7,77,000 J.
11. The amount of heat energy required to convert 1 kg
Calculate the specific latent heat of ice. Specific heat
2100 J kg-1 K-1, specific heat
capacity of water = 4200 J kg-1 K-1.
capacity of ice
how do we do it ?!​

Answer 1

Answer:

heat required to raise temperature is Q

Q=777000J=1×2100×10+1×L+1×4200×100

L=336000Jkg

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