Question

of initial velocity of an object in 20 km per hour at attains 5okm per hour in 5 minutes calculation distance and acceleration in 5 minutes​

Answer 1

Answer:

Step-by-step explanation:

Funny guy

Answer 2

Answer:a=580km/h

Step-by-step explanation:

u=20km/h

v=50km/h

t=5min

=1/12h

now from 1st eqn of motion

v=u+at

50=20+a×1/12

50×12=20+a

600-20=a

therefore a=580km/h

now,

from 2nd eqn of motion

s =ut+1/2 at sq.

s=20×1/1+1/2×580×1/12×1/12

i think the question is not correct