Question

of interest after 18 years.
(HOTS)
4. If pth term of an A.P. is - and qth term is , prove that the sum of the
first pq terms is [pq +1]
Hint : First find the values of a and d. Use the formula :
(n-1)d
(ii
(i) tn = a + (n -1)d
mil 2018
​

Answer 1

This is the answer and it is write.

Answer 2

Arithmetic Progression: if the pth term of an arithmetic progression is q and the qth term is p, then nth term is?

Let the pth term be (a + (p-1)*d) [where d is the common difference and a is the first term of the arithmetic progression].

Similarly, the qth term will be (a + (q-1)*d)

Now, using the given information:

a + (p - 1)*d = q ....(1)

a + (q - 1)*d = p ....(2)

Substracting (2) from (1), we get d = -1

Adding (1) and (2) and putting d = -1, we get

a = p + q - 1

As above, the nth term will be (a + (n-1)*d)

Substituting the values of a and d in this, we get

p + q - 1 + (n - 1)*(-1)

= p + q - 1 - n + 1

= p + q - n

Hence, we get that the nth term of the series is (p + q - n).

Step By Step

MAK ME Brainliest