Question

of mass 0.02 kg moving with a speed of 50 m/s enter a heavy wooden block and is stopped after of distance of 50cm . what is the average resistive force in N exerted by the block on the bullet?​

Answer 1

Answer:

please follow

Explanation:

Given,

m=0.04kg

u=90m/s

v=0m/s

S=60cm

From 3rd equation of motion,

2aS=v

2

−u

2

a=−

2S

u

2

a=−

2×60×10

−2

90×90

=−6750m/s

2

The resistive force, f=ma

f=−0.04×67.5

f=−270N