of mass 10 Kg is placed at a distance of 5 metres from the rear end of a long trolley as shown in figure the coefficient of friction between the block and the surface below is 0.2 starting from rest the trolley is given a uniform acceleration of 3 metre per second square the distance from the starting point will the block fall of the trolley is 3 X find the value of x
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Answers
The required displacement is 15m.
Given: A block of mass 10 Kg is placed at a distance of 5 metres from the rear end of a long trolley as shown in the figure the coefficient of friction between the block and the surface below is 0.2 starting from the rest of the trolley is given a uniform acceleration of 3 metres per second square.
TO FIND The value of X that is the displacement.
SOLUTION:
As we are given,
Pseudo force on block F as given in the question= 10 × 3 = 30N
The frictional force on block f as given in the question
= mg
= 0.2 x 10 x 10 = 20N
As we know,
Acceleration of block concerning trolley
a = F - f/m
= 30 - 20/10
= 1 m/s square
Also, the time taken by block to fall off trolley is 't'
S = 1/2 at square
5 = 1/2 * 1 * t
t = Root 10 s
Therefore, Displacement of the trolley in Root 10 s,
15 metre.
Therefore, the displacement is 15 m.
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